480x-40x^2=0

Solution for 480x-40x^2=0 equation:

480x-40x^2=0

a = -40; b = 480; c = 0;
Δ = b2-4ac
Δ = 4802-4·(-40)·0
Δ = 230400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{230400}=480$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(480)-480}{2*-40}=\frac{-960}{-80}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(480)+480}{2*-40}=\frac{0}{-80}
=0
$